Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{3} + 7 \, y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x + 5 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x = 5 \, y + 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + 4 \, x = 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,x^{2} + 5 \, y + 2 \, z = 4 \, w\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,3 \, w + 3 \, y = 6 \, x - 5 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 4 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x + 7 \, y = 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{3} + 6 \, x = 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,7 \, x^{3} y + 5 \, w z = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,3 \, w + y = x - 5 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 4 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} = 4 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,5 \, x + 2 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{3} + 6 \, x = 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x = 2 \, y + 2 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,7 \, w + 5 \, x = 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,y^{3} + x = 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,4 \, w + 7 \, x = 6 \, y + 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,y^{2} + 2 \, x = 2 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,y^{2} + 6 \, x = 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,6 \, w + 6 \, x = 6 \, y + 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 4 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,4 \, x + 3 \, y + 5 \, z = 5 \, w\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,x^{3} + 4 \, y + 4 \, z = 4 \, w\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x = 5 \, y + 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + x = 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + 7 \, x = 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x + 5 \, y + 5 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x + y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} + y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x + 2 \, y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,2 \, x y^{3} = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,y^{3} + 5 \, x = 5 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,4 \, w + 2 \, y = 6 \, x - 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 4 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x = z^{3} + 5 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x + 5 \, y + 2 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} - 7 \, z^{2} = x\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,2 \, x + 7 \, y = 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,7 \, x + y = 5 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x = z^{3} + 2 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} - 2 \, z^{2} = 6 \, x\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x + 3 \, y = 5 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} - 6 \, z^{2} = 6 \, x\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,2 \, x = 2 \, y + 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x = y^{3}\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,3 \, x = 5 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} - 5 \, z^{2} = 3 \, x\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,7 \, x + 4 \, y + 5 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} = 7 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,6 \, x + 2 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x^{2} + y + 3 \, z = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,7 \, x + 5 \, y = 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x + 3 \, y = 4 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,7 \, x = z^{3} + 3 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,6 \, x + 4 \, y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{3} + y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} = y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x + 4 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x + 7 \, y + 4 \, z = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,4 \, x^{2} y + 4 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,5 \, w + 7 \, x = 4 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,x = z^{3} - 5 \, w + 2 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x^{3} + 5 \, y + 3 \, z = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,2 \, x + 7 \, y + 3 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,6 \, x = y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,4 \, x y^{3} = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,w + 7 \, x = 2 \, y + 4 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,x^{2} + 7 \, y + 5 \, z = 5 \, w\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,7 \, x y^{2} = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,4 \, x = 6 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,5 \, w + 5 \, y = 3 \, x - 2 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,3 \, x^{3} y + 4 \, w z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x^{3} + y + 3 \, z = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x + 5 \, y + 3 \, z = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + 2 \, x = 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,2 \, x + 5 \, y = 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,5 \, w + 6 \, x = y + 4 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \\ w \end{array}\right] \middle|\,y^{3} + 6 \, x = 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 4 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 4 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} = 6 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,6 \, x = y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,3 \, x + y = 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + 4 \, x = 3 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x = z^{2} + 2 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x = 6 \, y + 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} + 6 \, x = 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,5 \, y = 3 \, x - 2 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y = 3 \, x - 3 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,4 \, x = z^{2} + 5 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,2 \, x = y^{3}\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,4 \, x = 4 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,2 \, x + y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{2} + 5 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,x^{3} = 2 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,5 \, x + 2 \, y = 0\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 2 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,7 \, x = z^{2} + 4 \, y\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y = x - 4 \, z\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(W\) is a subspace of \(\mathbb{R}^ 3 \) and \(U\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,x = 6 \, y + 4 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,6 \, x = z^{2} + 4 \, y\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,2 \, x + 5 \, y = 0\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \end{array}\right] \middle|\,5 \, x = y^{3}\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 2 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 2 \) and \(W\) is not.
Consider the following two sets of Euclidean vectors:
\begin{align*} U= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,2 \, x + 5 \, y = 5 \, z\right\} & & W= \left\{ \left[\begin{array}{c} x \\ y \\ z \end{array}\right] \middle|\,y^{2} - 2 \, z^{2} = 3 \, x\right\} \\ \end{align*}
Explain why one of these sets is a subspace of \(\mathbb{R}^ 3 \) and one is not.
Answer:
\(U\) is a subspace of \(\mathbb{R}^ 3 \) and \(W\) is not.